C6H6 + Br2 ----> C6H5Br + Hbr
(60.0g) (135.0g) (?g)
need to find the the grams of C6H5Br that were formed, how do you figure this out? from 60g c6h6 and 135g of Br2
thanks!
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C6H6 + Br2 ----> C6H5Br + Hbr
(60.0g) (135.0g) (?g)
need to find the the grams of C6H5Br that were formed, how do you figure this out? from 60g c6h6 and 135g of Br2
thanks!
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Answers (1)
It is no so hard...let's see
1)n(C6H6)=60.0g/78=0.77 mol
2)n(Br2)=135.0g/160 =0.84 mol
3)n(Br2>n(C6H6) then
n(C6H6)=n(C6H5Br)=0.84 mol
4)m(C6H5Br)=0.77*157=120.89 g