Calculate the energy level of the resulting excited state..

How would u do this?!?!

E=-RhZ^2[1/nf^2-1/ni^2]

nf^2=final energy level

ni^2=initial energy level

-Rh is 2178x10^-18

Z is the nuclear charge (how many protons)

and E is the change in energy

## Answers (1)

E = hc/λ

E = 6.6 x 10^-34 x 3 x 10^8 / 102.6 x 10^-9

E = 0.192 x 10^-17 J