Calculate the energy level of the resulting excited state..
How would u do this?!?!
E=-RhZ^2[1/nf^2-1/ni^2]
nf^2=final energy level
ni^2=initial energy level
-Rh is 2178x10^-18
Z is the nuclear charge (how many protons)
and E is the change in energy
Answers (1)
E = hc/λ
E = 6.6 x 10^-34 x 3 x 10^8 / 102.6 x 10^-9
E = 0.192 x 10^-17 J