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Use the inverse A^(-1) in (a) to solve.... have answer already don't know how to obtain.?

Use the inverse A^(-1) in (a) to solve Ax.

Ax=

[2]

[1]

[3]

the inverse for (a) is; (**dots just for spacing)

[1......-3......2]

[1/2....1...-1/2]

[-1.....-1......1]

answer should be

[1]

[1/2]

[0]

can someone explain how this answer is obtained. 10pts for explanation

Answers (3)

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t4zr0nmtaa profile image
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06rw9cwhaa profile image

The numbers you have given do not agree with the answer you gave.

This method of solution is based on the fact that if

AX = B where A is the matrix of coefficients and B is the matrix of constants, then

A^-1AX = A^-1B and A^-1A = I where I is the identity matrix so

X = A^-1B

The numbers you have given for A^-1 and B yield x = 5, y = 1/2, and z = 0.

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jq3we5gyaa profile image

Just multiply Ax by A^-1 on the left.

Reference: Verified on TI-84 calculator.