One liter of alcohol (1000 cm^3) in a flexible container is carried to the bottom of the sea, where the pressure is 2.6x10^6 N/m^2. What will be its volume there?

The Bulk Modulus value for alcohol is 1.0x10^9.

I think you use the equation B = Change in P / (Change in v / v)

The answer is 997 cm^3... How do you get that??

## Answers (1)

set delta v /v = 1/B(delta P) where B is the Bulk Modulus constant found in your physics book

Delta V / 1000 cm^3 = 2.6X10^-3

Delta V = 2.6 cm^3

1000 cm^3 - 2.6 cm^3 = 997 cm^3 after sig figs.