One liter of alcohol (1000 cm^3) in a flexible container is carried to the bottom of the sea, where the pressure is 2.6x10^6 N/m^2. What will be its volume there?
The Bulk Modulus value for alcohol is 1.0x10^9.
I think you use the equation B = Change in P / (Change in v / v)
The answer is 997 cm^3... How do you get that??