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The pH of .10 M (CH3)3NHCl (aq) is 5.40. What is the value of Kb for (CH3)3N?

I can't figure this one out

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(CH3)3NHCl is a strong salt >> (CH3)3NH+ + Cl-

pH = 5.40 >> [H+] = 3.98 x 10^-6

(CH3)3NH+ << >> (CH3)3N + H+

at equilibrium

0.10- 3.98 x 10^-6..... 3.98 x10^-6....3.98x10^-6

K = 1.58 x 10^-10 = Kw / Kb

Kb = 6.33 x 10^-5