Write the slope-intercept form of the equation of the line passing through the point (4,4) and perpendicular to the line y= 4/7 x - 5. I know the slope will have to be -7/4 but how do I find the y-intercept?

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## Answers (4)

the y-int. is -5

in the equation: y=m x + b, the b is the y-int.

slope intercept form is y= y1 + m(x - x1)

so put ur slope in... y = y1 + -7/4(x - x1)

now put in your points (4,4) y = 4 + -7/4(x - 4)

so now simplify y = 4 + -7/4x - 7

y = -7/4x - 3

+3 +3

y +3 = -7/4x

-7/4

y + 1.71 = x

answer x = 1.71

Reference:my 8th grade mind.I suggest you substitute the point in your equation:

Y=-7/4x+b

4=-7/4(4)+b

4=-28/4+b

4=-7+b ADD 7 TO BOTH SIDES SO YOU CAN CANCEL OUT

4+7=b

11=b

Therefore: y=-7/4x+11

y -y1 = m (x-x1)

with point (4,4) and the slope is -7/4 u plug 4 to y1 and 4 to x1

y - 4 = -7/4(x-4)

y = (-7/4)x + 11 with 11 is y intercept of the line that perpendicular with the original equation given

while y = (-7/4)x + 11 is the equation of the new line.