We're a place where learners ask for help for their tasks and share their knowledge.
AT S.T.P. 1 mole of of any gas occupies 22.4 Liters. With the balanced coefficients: 2 NH3 yields 1 N2 + 3 H2, there is 102 grams of NH3. How do I find out the liters of N2 and H2 at S.T.P. ?
(I'm a senior in high school taking College Chemistry by the way)
For further actions, you may consider blocking this person and/or reporting abuse
Andrew S -Mayne of da House- -
Bizarre -
Sophie -
Jimmy Torres -
Cindy Cohen -
peaceee! :) -
Salah -
... -
DancerGirl -
Tony Martinez -
Jessie M -
Yahoo user -
Jay Twentyfourth -
→♥Ms.Maximus.=) -
ashley l -
World P -
Jack C. -
ices8tergurl_0910 -
Maya -
Bailey Mills -
Answers (1)
To find volume of N2:
1) convert mass of NH3 to moles:
102g x 1 mol / 17 g of NH3 = 6 moles of NH3
2) multiply by the stoichiometric ratio to find moles of N2:
6 mol NH3 x 1 mol N2 / 2 mol NH3 = 3 moles of N2
3) convert moles of N2 to mass of N2:
3 moles N2 x 28 g of N2 per mole = 84 g of N2
4) convert mass of N2 to volume using density of N2 at STP:
84 g of N2 / 1.2506 g/l = 67 liters of N2
To find volume of H2
1) multiply moles of NH3 by the stoichiometric ratio to find moles of H2:
6 mol NH3 x 3 mol H2 / 2 mol NH3 = 18 moles of H2
2) convert moles of H2 to mass of H2:
18 moles H2 x 2 g of H2 per mole = 36 g of H2
3) convert mass of H2 to volume using density of H2 at STP:
36 g of H2 / 0.0899 g/l = 400 liters of H2