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A person walks the path shown below. The total trip consists of four straight-line paths.
Path 1 is 20.0 m due east.
Path 2 is 160.0 m due south.
Path 3 is 100.0 m 30.0° south of west.
Path 4 is 180.0 m 60.0° north of west.
At the end of the walk, what is the person's resultant displacement?
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Answers (1)
Visualize a 2D vector space, starting at (0, 0)
After path 1 the new position is (20, 0)
After path 2 the new position is...
(20, 0) + (0, -160) = (20, -160)
After path 3 the new position is...
(20,-160) + (-100 cos30, -100 sin30) = (-66.6, -210)
After path 4 the position is...
(-66.6, -210) + (-180 cos60, 180sin60) = (-156.6, -54.1)