Need Chemistry help ASAP please?

atomic mass:

C = 12.011

H = 1.0079

ratios:

C = 85.60/12.011 = 7.1268

H = 14.40/1.0079 = 14.2871

C:H = 7.1268 : 14.2871

C:H = 1 : 2.00

Empirical formula = CH₂

`

Algebraically (mathemtically)

you have 'x number of carbon atoms per y number of hydrogen atoms'

each carbon is 12.011

for x carbons atoms = 12.011x mass of carbon atoms

each hydrogen is 1.0079

for y hydrogen atoms = 1.0079y mass of hydrogen atoms

total mass of carbon and hydrogen atoms = 12.011x + 1.0079y

percentage of ;

Carbon => (total mass of carbon / total mass of Hydrogen and Carbon) 100% = 85.60%

Carbon => (12.011x) / (12.011x + 1.0079y)100% = 85.60%

Carbon => (12.011x) = 0.8560(12.011x + 1.0079y)

Hydrogen => (total mass of hydrogen / total mass of Hydrogen and Carbon) 100% = 14.40%

Hydrogen => (1.0079y) / (12.011x + 1.0079y)100% = 14.40%

Hydrogen => (1.0079y) = 0.1440(12.011x + 1.0079y)

H / C = [ (1.0079y) = 0.1440(12.011x + 1.0079y) ] / [ (12.011x) = 0.8560(12.011x + 1.0079y) ]

H / C = [ (1.0079y) = 0.1440 ] / [ (12.011x) = 0.8560]

(1.0079y) /(12.011x) = 0.1440 / 0.8560

y/x = (12.011 * 0.1440) /(1.0079 * 0.8560)

y/x = 2.0047

y:x = 2:1

Empirical formula = CH₂

`