An iron ore sample contains Fe2O3 together with other substances. Reaction of the ore with CO produces iron metal:

Fe2O3 + CO ------> Fe +CO2

a.) Calculate the number of grams of CO that can react with .350 kg of Fe2O3.

b.) Calculate the number of grams of Fe and the number of grams oc CO2 formed when .350 kg of Fe2O3 reacts.

## Answers (1)

Looks like no body wants to answer it, so let us try it.

Start with balancing the equation first

Fe2O3 + 3 CO ------> 2 Fe + 3 CO2

mol wt of Fe2O3 = 56*2+48 = 160 MW of CO = 28

(a)

Now one mole of Fe2O3 or 160 g react with 3 moles of CO or 84 g of CO

then 350 g of Fe2O3 will react with 350*84/160 = 183.75 g of CO

(b) 350 g Fe2O3 = 350/160 = 2.1875 moles of Fe2O3

Now one mole of Fe2O3 gives 2 moles of Fe

then 2.1875 moles will give 2.1875*2 = 4.375 moles of Fe or 4.375*60 = 262.5 g of Fe

Similarly 1 mole of Fe2O3 produce 3 moles of CO2

then 2.1875 moles of Fe2O3 will give 2.1875*3 = 6.5625 moles of CO2 or 6.5625*44 = 288.75 g CO2

The last part you can calculate using CO also. From (a) you know you used 183.75 g of CO

From the equation, 3 moles of CO or 84 g will give you 3 moles of CO2 or 44*3 = 132 g CO2

then 183.75 g CO will give 183.75*132/84 = 288.75 g of CO2

There you have it