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Hi
I have the problem: Solid chromium III oxide reacts with chlorine gas and solid carbon to form solid chromium III chloride and gaseous carbon monoxide. Write a balanced equation.
I think the formula _Cr203 + _ Cl4C --> _CrCl3 + _CO is the correct unbalanced formula but am not 100% sure.. and I can't seem to balance it.
Can someone please help me?! Xo Marina
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Answers (3)
unbalanced:
Cr2O3 + C + Cl2 ----> CrCl3 + CO
Stages of balancing
conserve Cr atoms Cr2O3 + C + Cl2 ----> 2CrCl3 + CO
Then Cl atoms Cr2O3 + C + 3Cl2 ----> 2CrCl3 + CO
oxygens Cr2O3 + C + 3Cl2 ----> 2CrCl3 + 3CO
and Carbon
Cr2O3 + 3C + 3Cl2 ----> 2CrCl3 + 3CO
Which is why you could not balance with CCl4 instead of separate C and Cl2 - C and Cl atoms are not in a 1:4 ratio but 1:2
Reference: chemical engineer
The correct balanced equation would be:
Cr2O3+3Cl2+3C--->3CrCl3+3CO
Whenever it states that one compound reacts with one element and another element, it means they are two different reactants.
Cr2O3 + C + Cl2 --------> CrCl3 + CO (balance Cr)
Cr2O3 + C + Cl2 --------> 2 CrCl3 + CO (balance Cl)
Cr2O3 + C + 3 Cl2 --------> 2 CrCl3 + CO (balance O)
Cr2O3 + C + 3 Cl2 --------> 2 CrCl3 + 3 CO Balance C)
Cr2O3 + 3 C + 3 Cl2 --------> 2 CrCl3 + 3 CO (done)