OK, I really need an easy way to do this, because I'm very confused on how it's suppose to work.

One math problem

4b^2 - 22b + 10

now i have the answer, I'm just confused as to how to get it.

2(2b - 1)(b - 5)

I need help big time, because I have been working on this homework for 2 days now and it's on 19 problems and I'm still not getting it. Someone please help me.

## Answers (3)

Okayyy. First, in factoring you approach the problem first with determining any least common factors. In 4v^2-22b+10 you have a least common factor of 2. If you factor out the 2 out of the entire trinomial, you get 2(2b^2-11b+5). (This is true because if you distribute the two into the parentheses you get 4b^2-22b+10). Now that you have this, you will focus on what's on the INSIDE of the parenthesis to factor further. There are several ways of approaching this, but this is how I would do it: The first terms inside the parentheses must have the variable, b, in it. You have to find two factors, that both have the variable, b, that will give you 2b^2. The only possibilities in this case are 2b and b. Therefore, you can conclude this: 2(2b ___)(b ____). Then, you have to find two numbers that, when one is multiplied by 2b, and the other by b (because these are the two factors you have as your first terms in the parentheses), you get -11b. By guess and check, you find that 5 and 1 are your two digits--5 times 2b is 10b. 1 times b is 1b. 10b + 1b is 11b...To get -11b you simply make 5 and 1 both negative. You will place these numbers in the set of parentheses OPPOSITE of the term you are multiplying them by. To get -11b, you multiply -5 by 2b, so -5 will go in the set of parentheses that does not have 2b. Same goes for -1b. Now you have 2(2b - 1)(b - 5). Tada!

Reference:my knowledgefirstly you take out the common factor of all three terms (the thing that divides by a aspects of equation) - in this case it is 2. so divide everything by 2 to get 2(2b^2-11b+5).

next you leave the 2 that you have already factored out and focus on the 2b^2-11b+5.

you factorises this to get (2b-1)(b-5)

finally you put the 2 back at the front of the equation to get 2(2b-1)(b-5)

hope this helps :)

1.) Find the greatest common factor.

-which would be 2.

2.)Divide everything by 2

2(2b-11b+5)

3.)Factor out (2b-11b+5)

-you have to guess a little.

-then you get

(2b+1) (1-5)

4.)Just place the 2 in front of that and your done.

2(2b+1)(1-5)

Reference:I took Algebra 2 Honors last year.