If the tension in each chain at the lowest point is 408 N, find the child’s speed at the lowest point.

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## Answers (1)

From a free body diagram we have 2*408 - m*g = m*a where a = v^2/R

816 - 49*9.8 = 49*v^2/1.5

so v = sqrt(1.5/48(816-49*9.8)) = 3.21m/s