There are a total of ___ atoms in 435g of the compound KPF6 (Molar mass = 184 g/mol)

Is it; (435g)X(1 mol/184g)X(6.02x10^23/1 mol) = 1.42X10^24 atoms?

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There are a total of ___ atoms in 435g of the compound KPF6 (Molar mass = 184 g/mol)

Is it; (435g)X(1 mol/184g)X(6.02x10^23/1 mol) = 1.42X10^24 atoms?

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## Answers (2)

Yes.

Given g x (1 mol/molar mass) x (6.022x10^23 atoms/1 mol) = ___ atoms

The sig figs is also correct.

I get the same answer!