from this equation .. how do you calculate how long something stays in the air.

h= -5t(squared)+15t+18

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from this equation .. how do you calculate how long something stays in the air.

h= -5t(squared)+15t+18

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## Answers (2)

h= -5t(squared)+15t+18

differentiate the equation:

dh/dt = -5X2 t + 15 = -10t+15...................(1)

Assuming that the projectile executes linear motion,

we know that at maximum height ( when object stays in air ), the rate of increase of height, dh/dt is zero.

so dh/dt=0

substituting in (1)

0= -10t+15

10t=15

t = 1.5 seconds

So object stays in air for 1.5 seconds.

Clear?

well from what i understand your calc for time is T, Height is H and gravity is G (9.81)

T^2 = height / .5g