A swimmer swims across a 20-meter-wide river at 0.3 m/s. The river is running at 0.1 m/s. What is resultant velocity of the swimmer, and at what angle, with respect to his original direction?

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## Answers (1)

v = sqrt(0.3² + 0.1²) m/s = 0.32 m/s = 0.3 m/s (significant figs)

Θ = arctan(0.1/0.3) = 18º w/r/t his original direction