A rock is thrown vertically into the air and reaches a height of 25.8 m. What is its speed when it is half way back to the ground?

And the answer is 15.90m/s

I need to know how to get that, and the process on how to get that so I could do a problem like that later. Thanks! :)

## Answers (1)

e = 1/2 g t^2

t = √ 2e /g = √ 25.8/9.8 = 1.6225s

v = g t = 15.9 m/s

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