a freezer has 5 orange ice pops, 4 lime ice pops, and 3 cherry ie pops. Suppose you pick an ice pop without looking and you keep the ice pop. Then you pick another ice pop without looking and keep it. Finally you pick a third ice pop without looking

What is the probability of picking an orange ice pop on the first pick a lime ice pop on the second pick and a cherry ice pop on the third pick?

please help

ty

5 minutes

## Answers (1)

P(orange ice pop) = Total number of orange ice pops/Total number of ice pops = 5/12

P(lime ice pop) = Total number of lime ice pops/Total number of ice pops = 4/12 = 1/3

P(cherry ice pop) = Total number of cherry ice pops/Total number of ice pops = 3/12 = 1/4

Reference:mathgoodies.com/lessons/vol6/intro...