how do you determine the equation of a circle that has diameter endpoints (-2,7) and (2,-7)
the equation format is r^2 = x^2 + y^2
thanks
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Answers (3)
mid point of diameter, which is the centre of circle is (0, 0)
radius = √(2² + 7²) = √53
equation is
(√53)² = (x−0)² + (y−0)²
answer
53 = x² + y².
First, find the midpoint between the 2 points:
x = (-2 + 2) / 2 = 0/2 = 0
y = (7 - 7) / 2 = 0/2 = 0
So, the circle is centered at (0 , 0)
The radius is the distance from the center to any point on the surface of the circle
(-2 - 0)^2 + (7 - 0)^2 = r^2
4 + 49 = r^2
53 = r^2
(x - 0)^2 + (y - 0)^2 = 53
x^2 + y^2 = 53
it is....you can plot points, or just memorize the formula. -_-
Reference: Ting ting Li gave me credit for embarrassing her wall.