There are 24 more sophomores than juniors in an 8 AM algebra class. If there are 78 students in this class, find the number of sophomores and the number of juniors in the class.

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## Answers (2)

Let n be the number of juniors and n + 24 be the number of sophomores.

n + (n + 24) = 78

2n + 24 = 78

2n = 54

n = 27

(n + 24) = 51

Juniors: 27

Sophomores: 51

there are 24 more sophomores than juniors:

s = j + 24

If 78 students total:

s + j = 78

Two unknowns, two equations. Solve with substitution:

s + j = 78

(j + 24) = j = 78

2j + 24 = 78

2j = 54

j = 27

s = j + 24

s = 27 + 24

s = 51

There are 51 sophomores and 27 juniors in the class.