If you throw a ball straight upward, it will rise into the air and then fall back down toward the ground. Imagine that you throw the ball with an initial velocity of 13.7 m/s. How long does it take the ball to reach the top of its motion?

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If you throw a ball straight upward, it will rise into the air and then fall back down toward the ground. Imagine that you throw the ball with an initial velocity of 13.7 m/s. How long does it take the ball to reach the top of its motion?

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## Answers (1)

Acceleration in free fall, due to gravity, is 9.8m/s^2 downwards, which means that for every second the speed of an object would increase by 9.8m/s as it falls towards earth.

In your question the velocity (or speed) of the ball is 13.7m/s upwards, when the ball is at the peak of its motion, before falling back down to earth, the speed will be 0. Since the ball is in free fall (in the air by itself) then gravity's acceleration affects it, which would mean that as it goes up its upward velocity(speed) will be decreased 9.8m/s every second.

Since gravity is constant you can make an equation to solve the problem.

S= I - 9.8(x) . S= Desired Speed of ball, I= Initial velocity of ball, 9.8= distance traveled in x seconds due to gravity's acceleration, X= time that has passed.

You are trying to find at what time (x in the equation) is the ball's speed 0.

so you would set it up like this. 0=13.7 - 9.8x

Using basic arithmetic you will find that x≈1.4 seconds

Reference:My Physics book =)