The equation of motion for an object in free fall starting from rest is y= 1/2gt^2, where g is the acceleration due to gravity. This is the equation of a parabola, which has the general form y=ax^2. Compute the experimental value of g from the slope value which is 4.8.

I have no idea what I'm supposed to be doing here. Anyone want to help?

## Answers (1)

You have measured values of y and t, right? Make a graph of y as a function of t². Since

y = (g/2) (t²)

you should be reminded of the equation of a line

y = m x + b

with b = 0 and x = t². So your graph is expected to be a line, with slope m = g/2. Find the slope of your graph (which can't possibly be 4.8, because your slope will have units, and 4.8 is just a number). Then solve for g.