What is the energy, in joules per photon if L= 2.31nm ?

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What is the energy, in joules per photon if L= 2.31nm ?

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## Answers (2)

Energy per photon in joules = Planck's constant times frequency

frequency = speed of light in meters per second over wave length in meters.

frequency = 3 x l0^8 meters per second over 2.31 x l0^-9th meters

frequency = 1.3 x 10^17th waves per second.

Energy per photon = 6.626 x 10^-34 J.s times 1.3 x l0^17th = 8.6 x l0^-17th joules/photon

Reference:retired chem teacher USAL, meaning lambda, Î»?

there are 2 equations:

C = Î»Ï

and E = hÏ

as both equations contain Ï

, frequency, we can write the equations to be equal to each other without using frequency.

C/Î» = E/h where C = 3x10^8m/s and h = 6.626x10^-34J-s

to determine E = Ch / Î»

convert nm to m, the easiest way is to just write 2.31x10^-9 (wavelength in m with the additional 10^-9, no matter what the value for m because it'll all work out in the end)

E = (3x10^8m/s x 6.626x10^-34J-s) / 2.31x10^-9m = 8.6x10^-17J