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Hello i am in AP chem this year and i forgot a lot over the summer. I worked this problem out but i want to make sure i did it correctly. The question is: How many moles of potassium hydroxide are needed to completely react with 3.47 moles of aluminum sulfate according to the balanced equation?
Equation: 6 KOH + 2 Al(OH)3 + 3 K2SO4
I got 20.82 moles of KOH
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Answers (1)
First, your equation is incomplete. I believe it should be:
Al2(SO4)3 + 6 KOH --> 2 Al(OH)3 + 3 K2SO4
You would do the calculation:
3.47 mol Al2(SO4)3 X (6 mol KOH / 1 molAl2(SO4)3) = 20.8 mol KOH.
You should only have 3 significant figures in your answer because your known quantity has only 3.