I need to factor these and I don't remember how...some help please...

3x^2 +10xy -25y^2

3y^2 +y -16

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I need to factor these and I don't remember how...some help please...

3x^2 +10xy -25y^2

3y^2 +y -16

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## Answers (3)

Okay - if you don't remember this could be tough!

First you look for common factors (neither of yours have any)

then you look for the difference of 2 squares (again, doesn't apply to you)

Then you are looking for a way to split them into 2 brackets (the opposite of what you do when you multiply brackets out)

(1) The first term (3x^2) can only be split into 3x and x, so your two brackets will start with one of these each

(3x )(x )

The last term is negative, This means that the signs in the brackets have to be one + and one - ( if both were the same, the result would have to be positive). The last term is 25y^2, which will split into either 5y and 5y or 25y and y. 5y and 5y is more likely, and in fact if you think about what happens when you multiply the brackets back out you van see that ou do need 5y and 5y.

(3x 5y)(x 5y). As the middle term is +10xy, we can now see that we need (3x+5y)(x-5y).

The final step is to multiply out these brackets just to check that you do, in fact, get back to the expression you started with.

Hope that has jogged your memory, and you can manage the other one yourself.

Check this site:

algebra.com/algebra/homework/quadr...

3x^2+10xy-25y^2+25=25

(3x+2.5)(x+10y) + (y+ really odd question, and I was in advanced pre-calculus. the double variable and constant product is why i refuse to answer.

(3y+4)(y-4)= your answer... almost.... why is there a stray "y"? I want to know what bok you got this from.... so I can learn.