I did all the other problems on my homework, but I don't know how to do this one...

An investor has $60,000 to invest. If part is invested at 8% and the rest at 14%, how much should be invested at each rate to yield 12% on the total amount?

Help please?

## Answers (1)

call x is the amount of money invested at 8% so 60000 - x is the amount invested at 14%

we have

.08x + 0.14(60000-x) = 60000*0.12

0.08x + 8400 - 0.14x = 7200

-0.06x = -1200

x = 20000$

So we have 20000$ invested at 8% and 40000$ invested at 14%

Hope this helps.