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In 1.00g of fluorine there are 3.12 x 10^22 fluorine atoms. If you started counting these atoms at the rate of 10 per second, how many years would it take to count all of the atoms in the sample?
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Answers (1)
(3.12x10^22)/10 = 3.12*10^21 seconds
(3.12x10^21)/(60*60*24*7*52) = number of years.
60 seconds in a minute, 60 mins in an hour, 24 hours in a day, 7 days a week and 52 weeks a year.