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The question is sketch the graph of the equation :
x^2
4
-y^2
9
=
1
To begin sketching this graph, I thought that you were supposed to rewrite the top parts of the problem such as (x+0)^2 - (y+0)^2
so you would get (0,0) for the center of the graph?
and my other question is:
since 4 = 2^2 , and 9 = 3^2 , would the center be 3,2 ? or would that be how many units you move from (0,0) ?
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Answers (1)
Right on the first answer, the center is 0,0.
Why the second question about the center? It is wrong. What you just calculated are the axes of the ellipse.
Set y=0 and the x intercepts are 2 and -2 (the x axes)
Set x=0 and the y intercepts are at 3 and -3 (the y axes)
Look up the equation for an ellipse
(x/a)^2+(y/b)^2=1 where a and b are the axes and the ellipse center is at 0,0.